What is the gradient of the line passing through the point (1,2) and (5,5)? What is the equation of this line? What is the equation of the line perpendicular to this line that passes through the origin (0,0)?

Gradient of initial line = 3/4 Equation of initial line : y= 3/4x + 5/4 (4y = 3x + 5) Equation of perpendicular line : y= -4/3x 

Answered by Temilola A. Maths tutor

3032 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

X is a prime number higher than the square of 5 and lower than the square of 7. What are the smallest and largest possible values for X?


The point P has coordinates (3,4), Q has the coordinates (a,b), a line perpendicular to PQ is given by the equation 3x+2y=7. Find an expression for b in terms of a


Factorise and simplify the following equation: (2x^2 + 5x + 3) / (x + 1)


Solve the equation ((2x+3)/(x-4))-((2x-8)/(2x+1))=1


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy