Find the stationary points of the curve y=2*x^3-15*x^2+24*x+17. Determine whether these points are maximum or minimum.

First, differentiate and put the derivative equal to zero. dy/dx=6x^2-30x+24=0. Solve this equation to get that x=4 and x=1. Substitute these values into the original equation to get the corresponding values of y. The stationary points are (1,17) and (4,-10). Calculate the second derivative to get d^2y/dx^2=12*x-30. When x=1 the second derivative is less than zero so (1,17) is a maximum point and when x=4 the second derivative is greater than zero so (4,-10) is a minimum point.

SM

Related Maths A Level answers

All answers ▸

Given that (2x-1) : (x-4) = (16x+1) : (2x-1), find the possible values of x


Find the values of x such that: (log3(81)+log2(32))/(log2(x)) = log2(x) (5 marks)


Why does the product rule for differentiating functions work?


How do I find a stationary point? And how do I determine whether it is a maximum or minimum point?