Find the stationary points of the curve y=2*x^3-15*x^2+24*x+17. Determine whether these points are maximum or minimum.

First, differentiate and put the derivative equal to zero. dy/dx=6x^2-30x+24=0. Solve this equation to get that x=4 and x=1. Substitute these values into the original equation to get the corresponding values of y. The stationary points are (1,17) and (4,-10). Calculate the second derivative to get d^2y/dx^2=12*x-30. When x=1 the second derivative is less than zero so (1,17) is a maximum point and when x=4 the second derivative is greater than zero so (4,-10) is a minimum point.

SM
Answered by Shaun M. Maths tutor

4440 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Simplify the following algebraic fraction; (3x^2 - x - 2) / ((1/2)x + (1/3)).


How do you express partial fractions of a proper fraction that has a denominator of (x-2)(x+1)^2


A particle of mass m is placed on an slope with an incline 30 degrees. Once released it accelerates down the line of greatest slope at 2 m s^-2. What is the coefficient of friction between the particle and the slope?


Differentiate the following... f(x)= 5x^4 +16x^2+ 4x + 5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning