How would I find a the tangent of a point on a line?

You will end up with an equation with the form y = mx + c you should be familiar with from GCSE First you would need to differentiate the equation of the line For example if you had f(x) = x3 + 2x and the coordinates (3,1) you get f'(x) = 3x2 + 2 Next input the values of x and y to gain the value of "m", You will get m = 5 Now, inputting the values of x, y and m you should finally obtain the value for c, in this case it would be -2

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Find the equation of the line that is perpendicular to the line 3x+5y=7 and passes through point (-2,-3) in the form px+qy+r=0


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In this question, take 'log' to mean 'log base 5'. Solve the equation log(x^2-5)-log(x) = 2*log(2)