Where do the graphs of y=3x-2 and y=x^2+4x-8 meet?
In order to find the points where these functions meet, we can equate them to get 3x-2 = x^2+4x-8 .
Subtraction (3x-2) from both sides, we get x^2+x-6 =0 which we can factorise to get (x+3)(x-2)=0
Therefore x=-3 or x=2 , and we can then get the values of y from this.
So the final answers are (-3, -11) and (2,4)
HS
Related Maths A Level answers
All answers ▸Sketch the graph y=-x^3, using this sketch y=-x^(1/3)
a)Given that 10 cosec^2(x) = 16 - 11 cot(x) , find the possible values of tan x .
Core 3: Find all the solutions of 2cos(2x) = 1-2sin(x) in the interval 0<x<360
"Why is Mathematics important, I wont use any of it when I start work?"