Differentiate x^2 + xy + y^2 =1 implicitly.

Each part can be done separately, so x^2 becomes 2x, xy becomes dy/dx + y by product rule, y^2 becomes 2y(dy/dx) by chain rule, and 1 becomes 0. Hence the answer is 2x + y + (2y+1)dy/dx = 0, but the answer is commonly given in the form dy/dx = -(2x+y)/(2y+1)

TD
Answered by Tutor80806 D. Maths tutor

4529 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Using Discriminants to Find the Number of Roots of a Quadratic Curve


Given that y=sin2x(3x-1)^4, find dy/dx


If y = 2/3 x^3 + x^2; a) What is dy/dx? b) Where are the turning points? c) What are the nature of the turning points?


differentiate 4x^3 + 3x^2 -5x +1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences