Solve the Simultaneous equation: 4x+y=25, x-3y=13

Firstly, try and make one of the variables (x or y) the same in both equation, in this instance because we have a positive and negative y if we add them, they will cancel out. Therefore multiply the first equation by 3 so we have 3y on both equations, giving us 12x+3y=75. Now we can add both equations together, which eliminates the y (-3y+3y = 0) leaving with 13x = 91. Now we simply find x by dividing 91 by 13 and getting an answer of x = 7. Now that we know x = 7 we can simply sibstitiute into any equaton, to find out the answer. For ease I will use the first equation. As x = 7, 4x = 28 so therefore 28 + y = 25. To find y we simply subtract 28 from both sides leaving us with y = -3. X = 7, Y = -3

AK
Answered by Anas K. Maths tutor

3898 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise 3x^2+15x


Solve the simultaneous equations: x^2 + y^2 = 5 and y = 3x + 1


Tom's dad is 3 times older than him. In 15 years the sum of Tom's and his dad's ages will be equal to 102. How old are Tom and his dad now?


Complete the square of the following expression: 2x^2 -8x+21


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences