A particle is moving along a straight line. The fixed point O lies on this line. The displacement of the particle from O at time t seconds is s metres where s = 2t3 – 12t2 + 7t(a) Find an expression for the velocity, v m/s, of the particle at time t.

To find velocity you differentiate displacement with respect to time

Therefore ds/dt = v = (3x2)t2-(12x2)t2+7

Implying v = 6t2-24t+7

TO
Answered by Thomas O. Maths tutor

24703 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A ball, dropped vertically, falls d metres in t seconds. d is directly proportional to the square of t. The ball drops 45 metres in the first 3 seconds. How far does the ball drop in the next 7 seconds?


How could you sketch a graph for y=x^2-10x+21?


How do you solve the following simultaneous equations? Equation 1: 2x + 3y = 13 Equation 2: 3x - y = 3


Factorise and solve 3x^2-x-10=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning