Given that y = 8x + 2x^-1, find the 2 values for x for which dy/dx = 0
First differentiate y with respect to x, which gives you dy/dx = 8 - 2x^-2. This needs to equal zero so equate to zero. 8-2x^-2 = 0. You can then bring the 2x^-2 to the other side giving 2x^-2=8. Dividing both sides by 2 gives x^-2 = 4. You can then flip both sides, giving x^2 = 1/4. Then square root both sides giving x = +/- 1/2.
RB
Related Maths A Level answers
All answers ▸The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.
The volume of a cone is V = 1/3*pi*r^2*h. Make r the subject of the formula.
If the function f is defined as f= 1-2x^3 find the inverse f^-1
y = 2/x^3 find and expression for dy/dx