Differentiate y=(3x-1)/(2x-1)

First, recognise that the function is a fraction and recall the quotient rule.     y=u/v     dy/dx=(vu'-uv')/v², where u' and v' is the derivative of u and v respectively. Then, apply the rule.     u=3x-1, v=2x-1     u'=3, v'=2     dy/dx=[3(2x-1)-2(3x-1)]/(2x-1)² Finally, simplify the expression.     dy/dx=1/(2x-1)²