Make y the subject of the equation: t=(y+2)/(4-y)
Multiply by 4-y => t(4-y)=y+2 Expand the brackets => 4t-ty=y+2 Get all the y's on the same side => 4t-2=ty+y Factor out the y => 4t-2=(t+1)y Divide by t+1 => (4t-2)/(t+1)=y
CM
Related Maths GCSE answers
All answers ▸Solve the following simultaneous equations: (1) 2y + x = 8, (2) 1 + y = 2x
f(x)=cos(x), g(x)=2+cos(x-1), state g(x) as a vector applied to f(x)
Solve simultaneous equations x + y = 3 and -3x + 5y = 7
Simplify, leaving your answer as a quadratic: (2x + 3)/(x+4) - (3x - 6) = 4