There is a bag of blue, red, and white counters. 1/6 of the bag is blue counters. 1/4 of the bag is red counters. What is the smallest number of white counters that could possibly be in the bag.
6 and 4 are common factors of 24.
1/6 = 4/24, and 1/4=6/24.
4/24+6/24 =10/24 of the bag is blue and red counters. Therefore, 24/24-10/24=14/24 of the bag is white counters.
14/24 can be simplified to 7/12.
ANSWER: Therefore, the smallest number of white counters possible in the bag is 7.
AC
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