Integral of (2(x^3)-7)/((x^4)-14x)
Set f(x)= (x^4)-14x. f’(x)=4(x^3)-14=2(2(x^3)-7). Thus we can write (2(x^3)-7)/((x^4)-14x)=(1/2)f’(x)/f(x). The integral of f’(x)/f(x)=ln|f(x)|+c. Thus the integral of (2(x^3)-7)/((x^4)-14x) is (1/2)(ln|f(x)|+c)=(1/2)ln|(x^4)-14x|+C.
IK
Related Maths A Level answers
All answers ▸The curve C has equation 4x^2 – y^3 – 4xy + 2^y = 0 The point P with coordinates (–2, 4) lies on C . Find the exact value of dy/dx at the point P .
How do I integrate by parts?
Given that Sin(A) = 1/sqrt(3), show that Tan(A) = 1/sqrt(2)
Differentiate 2e^(3x^2+6x)