sin(x)/(cos(x)+1) + cos(x)/(sin(x)+1) = 1

sin^2(x) + sin(x) + cos^2(x) + cos(x) = cos(x)sin(x) + cos(x) + sin(x) +1

(sin^2(x) + cos^2(x) =1) Therefore;

1 +sin(x) + cos(x) = cos(x)sin(x) + sin(x) +cos(x) +1

Cancelling out on both sides

cos(x)sin(x) = 0

Solution: cos(x)=0 x=pi/2 + kpi sin(x)=0 x= 0+ kpi 

JO

Related Maths A Level answers

All answers ▸

Use the substitution u = 6 - x^2 to find the value of the integral of (x^3)/(sqrt(6-x^2)) between the limits of x = 1 and x = 2 (AQA core 3 maths


How do I differentiate a pair of parametric equations?


Differentiate with respect to x and write in its simpliest form, Y=(2x-3)/x^2?


The mass, m grams, of a substance is increasing exponentially so that the mass at time t hours is m=250e^(0.021t). Find the time taken for the mass to double in value.