ln(2x^2 +9x-5) =1+ ln( x^2+2x-15)
Moving Ln to one side ln(2x^2 +9x-5) - ln( x^2+2x-15) =1 Subtracting Ln is the same as dividing ln(((2x^2 +9x-5)/( x^2+2x-15)) ln((2x-1)/(x-3))=1 Taking e to both sides (2x-1)/(x-3)=e x=(1-3e)/(2-e)
RH
Related Maths GCSE answers
All answers ▸Part 1 of a test has 60 marks, Part 2 has 100 marks. James scores 75% on part 1 and 48% on part 2. To pass the full test, he needs 60% of the total marks, does he pass?
How do you multiply out two brackets?
a)Rearrange the folowing to make m the subject; 4(m-2) = t(5m+3)
Simplify: y+y-x×x