ln(2x^2 +9x-5) =1+ ln( x^2+2x-15)

Moving Ln to one side ln(2x^2 +9x-5) -  ln( x^2+2x-15) =1 Subtracting Ln is the same as dividing ln(((2x^2 +9x-5)/( x^2+2x-15)) ln((2x-1)/(x-3))=1 Taking e to both sides (2x-1)/(x-3)=e x=(1-3e)/(2-e)

RH
Answered by Raj H. Maths tutor

8675 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How many centimeters are there in 6.8 meters?


Solve x for (x)/(4x-1) = (6x+5)/(12x+31)


Solve the simultaneous equations. (1) 2x + y = 18 (2)x − y = 6


Expand (x+4)(x-4)=33 to give values of x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning