ln(2x^2 +9x-5) =1+ ln( x^2+2x-15)
Moving Ln to one side ln(2x^2 +9x-5) - ln( x^2+2x-15) =1 Subtracting Ln is the same as dividing ln(((2x^2 +9x-5)/( x^2+2x-15)) ln((2x-1)/(x-3))=1 Taking e to both sides (2x-1)/(x-3)=e x=(1-3e)/(2-e)
RH
Related Maths GCSE answers
All answers ▸How do I solve quadratic equations by factorization?
given that (x+8)^2-62=ax^2+bx+c find the values of a,b and c (3 marks)
How to factorise a quadratic with a coefficient of x^2 greater than one, for example 4x2+4x-15?
Solve the simultaneous equations: 5x + y = 21, x - 3y = 9