Rearrange the following making a the subject: (a+2)/5 = 3a+b
(a+2)/5 = 3a+b ...first, we need to multiply both sides by 5
a + 2 = 5 (3a + b) ....to be able substract 3a from the right side we need to remove the bracket. We multiply the bracket by 5.
a + 2 = 15a + 5b ...now we need to make sure all element containing a are on the same side of the equation. We do -a and -5b
a + 2 -a -5b = 15a + 5b - a - 5b ...to make it easier to imagine, we can write the equation like this
2 - 5b = 14a ...Finally, we need to make 1a the subject so we devide the equation by 14
(2-5b) / 14 = a ...Congratulations!!!
KR
Related Maths GCSE answers
All answers ▸2X-6=4
Given that 7/9 = 0.77777777 (recurring) convert 0.27777777(recurring) into a fraction. Give your answer in the simplest form.
32sqrt 2 = 2^a, find the value of a
There are three boxes and one has a prize inside. You are told to choose a box. One of the other boxes is then opened, showing that it is empty. You are given the option to switch your choice to the other remaining box. Should you switch? Why?