Rearrange the following making a the subject: (a+2)/5 = 3a+b
(a+2)/5 = 3a+b ...first, we need to multiply both sides by 5
a + 2 = 5 (3a + b) ....to be able substract 3a from the right side we need to remove the bracket. We multiply the bracket by 5.
a + 2 = 15a + 5b ...now we need to make sure all element containing a are on the same side of the equation. We do -a and -5b
a + 2 -a -5b = 15a + 5b - a - 5b ...to make it easier to imagine, we can write the equation like this
2 - 5b = 14a ...Finally, we need to make 1a the subject so we devide the equation by 14
(2-5b) / 14 = a ...Congratulations!!!
KR
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