Complete this substitution question: x^​3 - 25 = 103 - x^​3

Firstly, let's move the x^​3's onto the same side (and preferably keep them positive). Let's add x^​3 to both sides, which means the RHS will now read '2x^​3 - 25' and the LHS will read '103'. Next we want to get the numbers onto the same side, so let's add 25 to both sides (again, to keep the numbers positive). This leaves us with 2x^​3=128. Next we need to divide both sides by 2 (to get rid of the 2 in from of the x^​3 term). This means x^​3=64. After cube routing both sides, we have arrived at our answer of 'x=4'.

AJ

Related Maths GCSE answers

All answers ▸

Solve 5w – 3 = 3w + 15


Triangle PQR is a right angled triangle. PQ is the hypotenuse and is 5cm long and QR has length 3cm. What is the length of side PR? Show your working.


Can you solve these simultaneous equations and find the values of x and y? Equation 1: 2x + y = 14 Equation 2: 4x - y = 10.


How do you expand brackets?