Integrate 5cos(3x - 1) with respect to x
Firstly, we may simplify the expression by factoring out any constants. In this case 5 can be factored out.
5 ∫ cos(3x-1) dx
For the integrand cos(3x -1), we can use a simple u-substitution. Where u = 3x -1 and du = 3dx.
Our integral is then simplified to 5 ∫ cos(u) du/3
The integral of cos(u) is equal to sin(u)
And therefore the solution becomes: (5/3)*sin(u) + constant
Subsituting for u: (5/3)*sin(3x-1) + constant
RM
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