find dy/dx at t, where t=2, x=t^3+t and y=t^2+1

We know from simple fraction rules that dy/dx=(dy/dt)/(dx/dt). dy/dt=2t, dx/dt=3t^2+1. Therefore, dy/dx=2x2/12+1=4/13

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Answered by Niamh O. Maths tutor

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