Suppose we have a circle whose radius is 5cm. If a sector of this circle has an area of 15 cm^2, what is the size its angle (in degrees)?

Firstly, you would need to figure out what formula you can use to solve this problem. You know the radius and area of the sector, and you need to find the angle. So, the correct equation to use would be the formula for the area of a sector: A = θ/360 x πr2 . Substituting 15 for A and 5 for r, we have 15 = θ/360 x 25π. We then want to make θ the subject of our equation, so we need to multiply both sides by 360, and then divide both sides by 25π. Finally, we have our solution: θ = (15x360)/25π = 68.8 (in 3 s.f.).

RS
Answered by Roxani S. Maths tutor

3032 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Draw the graph y=4x+2


Triangle PQR is a right angled triangle. PQ is the hypotenuse and is 5cm long and QR has length 3cm. What is the length of side PR? Show your working.


Maths A Level: "Sketch the curve of the function f(x) = 2x^3 - 2x - 12 and show that the equation f(x)=0 has one root; calculate the root."


How do I solve this linear equation? Angles A and B are in a quadrilateral are in ratio 2:3, angle C is 30 degrees more than angle B and angle D is 90 degrees.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences