The mass, m grams, of a substance is increasing exponentially so that the mass at time t hours is m=250e^(0.021t). Find the time taken for the mass to double in value.

All exponential equations can be reduced to the form m=m0ekt, where m0 is the initial mass. This means for our equation the initial mass is 250g. If the mass has doubled in size, then m now equals 2*250 = 500g. Plugging this into our exponential equation gives us 500=250e0.021t , which we can then work through as follows to re-arrange for t:

e0.021t = 500/250 = 2

0.021t = ln(2)

t = ln(2) / 0.021 = 33.0070086 = 33.0 hours (3 significant figures)

TJ

Related Maths A Level answers

All answers ▸

Find the gradient of the exponential curve y(x)=(9e^(7x))/(12e^(2x)) at x=2/5


The functions f and g are defined by f : x → 2x + ln 2, g : x → e^(2x). Find the composite function gf, sketch its graph and find its range.


Differentiate f(x) = (3x + 5)(4x - 7)


Show that x^2 - x +2 is positive for all values of x