The mass, m grams, of a substance is increasing exponentially so that the mass at time t hours is m=250e^(0.021t). Find the time taken for the mass to double in value.

All exponential equations can be reduced to the form m=m0ekt, where m0 is the initial mass. This means for our equation the initial mass is 250g. If the mass has doubled in size, then m now equals 2*250 = 500g. Plugging this into our exponential equation gives us 500=250e0.021t , which we can then work through as follows to re-arrange for t:

e0.021t = 500/250 = 2

0.021t = ln(2)

t = ln(2) / 0.021 = 33.0070086 = 33.0 hours (3 significant figures)

TJ
Answered by Tom J. Maths tutor

8694 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I express y=acosx+bsinx in the form y=Rcos(x-c)?


By integrating, find the area between the curve and x axis of y = x*exp(x) between x = 0 and x = 1


X=4x^2 + 5x^7 - sin(3x) find dy/dx


Differentiate x^3 − 3x^2 − 9x. Hence find the x-coordinates of the stationary points on the curve y = x^3 − 3x^2 − 9x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning