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y=4x/(x^2+5)

Find dy/dx

Remember quotient rule dy/dx=(u'v-v'u)/v^2

u=4x u'=4

v=x^2+5 v'=2x

dy/dx=(20-4x^2)/(x^2+5)^2 (simplified)

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Answered by Jeppe S. • Maths tutor

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