When (x – 2)^2 + 7 has a minimum value, what is the value of x?

First, expand (x-2)2:

= (x-2)(x-2),

= x2 - 2x - 2x + 4

= x2 - 4x + 4

Add on the +7:

= x2 - 4x + 11

complete the square

= (x - 2)2 - 4 + 11

= (x - 2)2 + 7

when the graph has a minumum value, (x - 2) = 0,

so x = 2

Answered by Tom L. Maths tutor

6062 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 13 counters in a bag. 4 counters are red, the rest are blue. Alice takes 2 counters without replacing them. What is the probability that both counters are the same colour?


How do I do algebra when there is an x on both sides?


Solve the inequality x^2+2x-8<0


Simplify fully {x^2 -3x -4}/{x^2 + 4x +3}


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences