How can do you factorize the equation x^2+6x+8
Here, we see that the term in x in the equation is 6, so we start by looking for a perfect square where the second term would be 6 : we get 6/2 = 3 so we try (x+3)2. However, (x+3)2 = x2+ 6x + 9. We thus have (x+3)2 - 1. We then use the fact that (a+b)(a-b) = a2 - b2 and obtain (x+2)(x+4) = x**2 + 6x + 8.
MS
Related Maths A Level answers
All answers ▸Consider the closed curve between 0 <= theta < 2pi given by r(theta) = 6 + alpha sin theta, where alpha is some real constant strictly between 0 and 6. The area in this closed curve is 97pi/2. Calculate the value of alpha.
How would we evaluate (1/3)^-3/2 ?
If z is a complex number, solve the equation (z+i)* = 2iz+1 where the star (*) denotes the complex conjugate.
How to differentiate the function f(x)= 3x^3 + 2x^-3 - x^(1/2) + 6?