In the case of cystic fibrosis, two parents don't suffer from the disease but both carry the recessive cystic fibrosis allele. What is the probability that a child of the parents will suffer from cystic fibrosis.

25%. Draw a punnet square to find this:

Write in the alleles for the parents along the top and side of the square, then match up the possible allele combinations for the children inside the square. 

Cystic fibrosis is a recessive allele, only people who carry the two recessive alleles (ff) will suffer from the disease. On the punnet square one of the four possible combinations for the child has two recessive alleles. The for the probabilty of a child getting the disease (as a percentage) is (1/4) x 100 % = 25 %

LD
Answered by Louis D. Biology tutor

4730 Views

See similar Biology GCSE tutors

Related Biology GCSE answers

All answers ▸

The MMR vaccine is given to children in order to prevent the conditions measles, mumps and rubella. Describe how a vaccine works?


Janice has cystic fibrosis. Cystic fibrosis is caused by a recessive allele (f). What is the probability of her baby having cystic fibrosis? The baby’s father is heterozygous for cystic fibrosis.


What are the word and chemical equations for photosynthesis?


Name the 4 different stages of Mitosis?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning