Find the coordinates of the two points where the lines y=x²+4x+6 and y=x+4 meet.

To solve these equations we must make them equal to eachother. This gives us x2+4x+6=x+4, we must then subtract the 'x+4' from both sides to give us an equation that equals 0. This gives us the following equation x2+3x+2=0. To solve this we can factorise it which gives us (x+1)(x+2)=0. To find the values of x we must make each bracket equal to 0 so we get x+1=0 -> x=-1 and x+2=0 -> x=-2. Now we have our values for x, we must find the y values, this can be done by substituting each x -value into our y equation (y=x+4). For x=-1, we get y=(-1)+4 -> y=3 so our coordinate is (-1,3), and for x=-2, we get y=(-2)+4 -> y=2 so our coordinate is (-2,2).

GH
Answered by Gaby H. Maths tutor

3076 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify (3a+b)(a-2b).


I don't understand how to solve quadratic inequalities?


How do you calculate arc length and sector area and why is it calculated like this? You are given sector angle 40 degrees and radius 7cm and asked to give answers to 3sf.


Show x^2 + 8x +15 = 0 in the form of (x+b)^2 +c (complete the square) and then solve the equation


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning