Solve the simultaneous equations (1) x + 3y = 7 and (2) 2x + y = 4

It's impossible to solve an equation with two unknowns (x and y) so we must find a way to get rid of either x or y before solving an equation. Using substitution rearrange the equation 1 so x is the only term on one side of the equation by subtracting 3y from both sides leaving: x = 7 - 3y. Substitute that into the second equation to get 2(7 - 3y) + y = 4 Expand the brackets 14 -5y = 4 which rearranges to 5y = 10 so y = 2 Substitute y = 2 back into equation 2 to get 2x + 2 = 4 which gives x = 1 Using elimination multiply equation (1) by 2: 2x + 6y =14. Both equations now contain 2 lots of x Subtract equation 2 from equation 1 to eliminate x 5y = 10 so y = 2 Substitute y = 2 into equation 2 2x + 2 = 4 so x = 1

SS
Answered by Simon S. Maths tutor

4603 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

1) 3x + y = 11 2) 2x + y = 8


Factorise fully x^2+6x+5=0


Dominik hires a satellite phone. His total hire charge is £860. For how many weeks did he hire the phone? (Total hire charge = No. of week X 90 +50)


Solve this simultaneous equation: (1) 2x+3y=12 (2) x+4y=11


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning