Find dy/dx for y = x^3*e^x*cos(x)

In this problem, we see that y is a product of 3 functions of x. That means that in order to find dy/dx we need to use the product rule. The product rule tells us that in this case we should differentiate one function at a time, keeping the others unchanged. That would mean that we will end with 3 terms - one for each function that we differentiate - multiplied by the other 2. So the solution here will be: firstly: d(x3 )/dx= 3x2 secondly: d(ex)/dx = ex thirdly: d(cos(x))/dx = -sin(x) and so the solution is: dy/dx = 3*x2*ex*cos(x) + x3*ex*cos(x) + x3ex(-sin(x))

LN

Related Maths A Level answers

All answers ▸

Integrate (sin(x))^6 - Further mathematics (De Moivre's theorem)


How do I use the chain rule to differentiate polynomial powers of e?


How do you express partial fractions of a proper fraction that has a denominator of (x-2)(x+1)^2


Find the x values for stationary points in the curve y=3sin(2x) for 0<x<180