Solve this pair of simultaneous equations: 3x + 2y = 4 and 2x + y = 3
2x + y = 3 therefore y = 3 - 2x
Substitute y = 3 - 2x in to the first equation:
3x + 2(3 - 2x) = 4
3x + 6 - 4x = 4
-x = -2 therefore x = 2
Substitute x = 2 in to either equation:
2(2) + y = 3
4 + y = 3
y = -1
TC
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