Solve this pair of simultaneous equations: 3x + 2y = 4 and 2x + y = 3

2x + y = 3   therefore  y = 3 - 2x

Substitute y = 3 - 2x in to the first equation:

3x + 2(3 - 2x) = 4

3x + 6 - 4x = 4

-x = -2   therefore x = 2

Substitute x = 2 in to either equation:

2(2) + y = 3

4 + y = 3

y = -1