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x = t^3 + t, y = t^2 +1, find dy/dx

dy/dx = dy/dt x dt/dx

x = t³ + t

dx/dt = 3t² +1

y = t² +1

dy/dt = 2t

dy/dx = 2t x (1 / (3t² +1) )

= 2t / (3t²+ 1)

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Answered by Sukhwinder K. • Maths tutor

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