Differentiate the following: 7x^2 - 3x^3 + 5 + 27x

To solve this, we mutiply the powers by their respective co-efficients, then we lower the power by 1. If there isn't any X value following the number, we ignore the number entirely because it is a constant.  So, 7 mutiplied by 2 = 14  This gives us 14x^2-1 = 14x  -3 multiplied by 3 = -9  This gives us -9x^3-1 = -9x^2 We ignore the 5 as it is a constant (there is no X value following it)  27x is the same as 27x^1, so if we mutiply the power by the co-efficient and lower the power, we are simply left with 27.  The final answer will thus read: -9x^2 +14x +27

OS
Answered by Oliver S. Maths tutor

2963 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: 2x + 2y = 14; 4x - 2y = 10


Solve the simultaneous equations: 12x - 4y = 12 (1) and 3x + 2y = 12 (2)


Work out (2^34) / (2^3)^10


Solve x^2 + 7x + 6 = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning