Differentiate the following: 7x^2 - 3x^3 + 5 + 27x

To solve this, we mutiply the powers by their respective co-efficients, then we lower the power by 1. If there isn't any X value following the number, we ignore the number entirely because it is a constant.  So, 7 mutiplied by 2 = 14  This gives us 14x^2-1 = 14x  -3 multiplied by 3 = -9  This gives us -9x^3-1 = -9x^2 We ignore the 5 as it is a constant (there is no X value following it)  27x is the same as 27x^1, so if we mutiply the power by the co-efficient and lower the power, we are simply left with 27.  The final answer will thus read: -9x^2 +14x +27

Answered by Oliver S. Maths tutor

2207 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve this linear equation? Angles A and B are in a quadrilateral are in ratio 2:3, angle C is 30 degrees more than angle B and angle D is 90 degrees.


Express x^2 + 10x – 3 in the form (x + p)^2 + q


Factorise x^2 - 8x - 20


Solve the inequality 6y+5>8?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy