solve the simultaneous equations 3x+7y=18 and 7x+9y=8

3x+7y=18 (eqn 1)  -multiply by 7->   21x+49y=126 (eqn 1*)

7x+9y=8  (eqn 2)  -multiply by 3->    21x+27y=24 (eqn 2*)

(eqn 1*)-(eqn 2*)  --> 22y=102 therefor y=51/11

sub in this y value back into (eqn1) -->  3x+7(51/11)=18 --> 3x+357/11=18 --> 3x=-159/11

therefore x=-53/11

RS
Answered by Radhika S. Maths tutor

3502 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If a line t (f(x) = 2x +3) is perpendicular to a line n that passes through point (3,7), what is the equation of line n?


Solve x^2 + 10x - 3 = 0


Solve the following simultaneous equations: 3y=7+5x (1) 9x=-7y-4 (2)


Expand the following : (2x+3)(x-1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning