solve the simultaneous equations 3x+7y=18 and 7x+9y=8

3x+7y=18 (eqn 1)  -multiply by 7->   21x+49y=126 (eqn 1*)

7x+9y=8  (eqn 2)  -multiply by 3->    21x+27y=24 (eqn 2*)

(eqn 1*)-(eqn 2*)  --> 22y=102 therefor y=51/11

sub in this y value back into (eqn1) -->  3x+7(51/11)=18 --> 3x+357/11=18 --> 3x=-159/11

therefore x=-53/11

RS
Answered by Radhika S. Maths tutor

3702 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I factorise a quadratic equation?


Simplify: 2x + 6y + 2y - x


Mike, Sam and James play football. Mike scores 8 more goals than James. Sam scores 5 more goals than Mike. Altogether they score 72 goals. How many did Sam score?


Calculate the area of a sector which has an acute angle of 30 degrees and a radius of 5cm.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning