Differentiate sin(x)*x^2
Notice that (sin(x))'= cos(x) and (x^2)' = 2x
We use the product rule to differentiate, by noticing the expression is a product.
so (fxgx)' = f'xgx + fx*g'x
substituting in we get (sin(x)*x^2) = cos(x)*x^2 + sin(x)*2x
DG
Notice that (sin(x))'= cos(x) and (x^2)' = 2x
We use the product rule to differentiate, by noticing the expression is a product.
so (fxgx)' = f'xgx + fx*g'x
substituting in we get (sin(x)*x^2) = cos(x)*x^2 + sin(x)*2x
