Find the x coordinate of the minimum point of the curve y = e3x - 6e2x + 32.

To find the minimum point of this curve you need to differentiate y and set it equal to zero before solving for x. If the questions does not say otherwise give your answer to 3 s.f. dy/dx = 3e^3x -12e^2x = 0 solving this for e^x gives : e^x =4 and you need to take the natural logarithm of both sides to find x. x=ln(4)