How do I differentiate 3^2x?
By recalling that eln(a) = a, you can rewrite 32x as e2xln(3).
Then, you can differentiate this like any other e function, by using the product rule.
d/dx (e2xln(3)) = e2xln(3) x d/dx (2xln(3))
d/dx (e2xln(3)) = e2xln(3) x 2ln(3)
LD
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