Given that y = 3x(^2) + 6x(^1/3) + (2x(^3) - 7)/(3(sqrt(x))) when x > 0 find dy/dx

Firstly, the (2x(^3) - 7)/(3(sqrt(x))) can be split into (2x(^3))/(3(sqrt(x)) and -7/(3(sqrt(x)). These can then be simplified to (2/3)x(^5/2) and -(7/3)x(^-1/2) respectively. This then gives the equation y = 3x(^2) + 6x(^1/3) + (2/3)x(^5/2) - (7/3)x(^-1/2).

By multiplying the coefficients of x by the power of x and then taking 1 from the power it is found that dy/dx = 6x + 2x(^-2/3) + (5/3)x(^3/2) + (7/6)x(^-3/2).

SH
Answered by Samuel H. Maths tutor

16000 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve x² ≥ | 5x - 6 | (Question from AQA Core 3 June 2016)


Solve the pair of simultaneous equations; (1) y + 4x + 1 = 0, (2) y^2 + 5x^2 + 2x = 0 .


There's a school in India where only 60% of students have internet access. What is the probability of choosing eight students randomly, five of whom have internet access? (Info: Each student's internet access (or lack of it) is independent from all others


(Core 3 level) Integrate the function f(x) = 2 -cos(3x) between the bounds 0, pi/3.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences