Differentiate the following function u = Cos(x3)

 u = Cos(x3)

To differentiate this function we will use the chain rule. Firstly we will set xto another variable name such as v. So now v = x3 . Lets differentiate this. dv/dx = 3x2

We can now differentiate cos(v) du/dv = -sin(v). Now to complete the chain rule we must do dv/dx*du/dv. Which will be -sin(v)*3x= -3x2sin(v). Now we can just put the x3 back in instead of the v and our final answer will be -3x2sin( x3).

SB

Related Maths A Level answers

All answers ▸

Integrate 2x^4 - 4/sqrt(x) + 3 dx


When you are working out dy/dx = 0, why do you do this and what does it mean?


How do you integrate sin(3x)cos(5x)?


Using the result: ∫(2xsin(x)cos(x))dx = -1⁄2[xcos(2x)-1⁄2sin(2x)] calculate ∫sin²(x) dx using integration by parts