[equ1] 3y − 6x = 3 [equ2] y y x 2 − x + 2 2 = 2

Firstly start by rearranging [equ1] to get y = 2x + 1 . Then substitute this result into [equ2] this will give you (2x + 1) (2x ) x . Simplify the equation and subtract two from both sides to 2 − x + 1 + 2 2 = 2 get an ordinary quadratic equation 4x x . Following on from this utilise the quadratic 2 + 3 − 1 = 0 formula x = . After using this equation the values for are . Then use the 2a −b±√b −4ac 2 x x =− 1, x = 4 1 rearranged form of [equ1] to find the values of y . Which, after evaluation, are y =− 1, y = 2

AS
Answered by Alistair S. Maths tutor

4029 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

3n+2 <= 14 and 6n/(n^2+5) > 1 Find possible values of N


what does a value shared in the ratio 2:3 mean?


f(x) = (x+1)^2 and g(x) = 2(x-1); Show that gf(x) =2x(x+2)


Denise buys 5 apples and 3 bananas for £3.15. A banana costs 25p more than an apple. How much would it cost to buy 4 apples and 2 bananas?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences