Answers>Maths>A Level>Article

Let y be a function of x such that y=x^3 + (3/2)x^2-6x and y = f(x) . Find the coordinates of the stationary points .

y = x³ + 1.5x²-6x Hence, dy/dx = 3x² + 3x - 6 Solve to find x when dy/dx = 0 as gradient is zero at stationary points Substitute the vaules for x back into y to find y coordinates of the stationary points. Then write out the coordinates as a final answer like so, (1,-7/2) and (-2,10)

Answered by Michael C. • Maths tutor

4473 Views

See similar Maths A Level tutors

Let y be a function of x such that y=x^3 + (3/2)x^2-6x and y = f(x) . Find the coordinates of the stationary points .

Related Maths A Level answers

Show that r^2(r + 1)^2 - r^2(r - 1)^2 ≡ 4r^3.

If y=2x+4x^3+3x^4 and z=(1+x)^2, find dy/dx and dz/dx.

How do you intergrate ln(x)?

When I try to integrate by parts, I end up in an infinite loop. Why is this, and how do you stop?