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Let y be a function of x such that y=x^3 + (3/2)x^2-6x and y = f(x) . Find the coordinates of the stationary points .

y = x³ + 1.5x²-6x Hence, dy/dx = 3x² + 3x - 6 Solve to find x when dy/dx = 0 as gradient is zero at stationary points Substitute the vaules for x back into y to find y coordinates of the stationary points. Then write out the coordinates as a final answer like so, (1,-7/2) and (-2,10)

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Let y be a function of x such that y=x^3 + (3/2)x^2-6x and y = f(x) . Find the coordinates of the stationary points .

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