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Differentiate implicitly with respect to x the equation x^3*y^5+3x=8y^3+1

3x²y⁵+5x³y⁴y'+3 = 24y²y'

3x²y⁵+3 = (24y²–5x³y⁴)y'

y' = (3x²y⁵+3) / (24y²–5x³y⁴)

Answered by Nora G. • Maths tutor

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