Substitute values of one equation into another.
(1) x+y+2z = -2; (2) 3x-y+14z=6; x+2y=-5 (3).
Substitute x in (1) and (2) from (3).
We get -y+2z=3 in (1).
We get -7y+14z=21 in (3).
Since (3) is (1)*7, we can conclude that the system has infinite solutions.
Answered by David G.
Answered by Olivia T.
Answered by Abby R.
Answered by Radovan S.