Solve the following equations x^2-2x+4=0, x^2+4x+1=0

x2-2x+4= (x-2)(x-2)=0  x=-2 (double root)  

x2+5x+1=0

x1,2= -5+_ (52-4(1)(1) )0.5/2 

x1=4.8     x2=-0.2 (to 1 d.p.)

KF
Answered by Kyriakos F. Maths tutor

2960 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

solve: 4x^2 + 6x - 4 > 0


Solve x^3 - 25 = 103 - x^3


Why do I have to study maths?


1ii) sketch y=x^2-4x-21


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences