Show that 6sin(60◦) + 5tan(60◦) can be written in the form √k where k is an integer.
sin(60◦) = √3 /2
tan(60◦) = √3
6sin(60◦) + 5tan(60◦) = 3√3 + 5√3 = 8√3 = √64√3 = √192
AG
sin(60◦) = √3 /2
tan(60◦) = √3
6sin(60◦) + 5tan(60◦) = 3√3 + 5√3 = 8√3 = √64√3 = √192
