Solve the equation ((2x+3)/(x-4))-((2x-8)/(2x+1))=1

Step 1: Multiply everything by x-4 to give 

(2x+3) - ((2x-8)(x-4)/2x+1)=(x-4)

Step2: Multiply everything by 2x+1 to give

(2x+3)(2x+1)-(2x-8)(x-4)=(x-4)(2x+1)

Step 3: Multiply out the brackets to give

(4x2+8x+3)-(2x2-16x+32)=2x2-7x-4

Step 4: Simplify to get a zero on one side of the equation to give

31x-25=0

Step 5: We therefore know that 31x = 25 so to find x divide 25 by 31 to get x=0.81 to 2 decimal places

MT
Answered by Matthew T. Maths tutor

8669 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

solve the simultaneous equation: 8x+2y=46; 7x+3y=47


Explain the use of the quadratic formula to solve quadratic equations.


2476 adults watch a cricket match. The ratio men : women is 3 : 1 How many more men than women watch the match?


Solve the simultaneous equations 2x + y = 7 and 3x - y = 8


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning