Find dy/dx for y=5x^3-2x^2+7x-15

Step 1: To differentiate an equation there is a simple rule to follow. For y=axn dy/dx=anxn-1. so for an example y=x3, dy/dx=3x2. Therefore we just apply this rule into our equation.

Step 2: Break the equation down and do each factor of x seperately so 5x3 differentiates into 15x2, -2x2 differentiates to -4x, 7x differentiates to 7 and the 15 disappears from the end. This happens as the 15 just tells us where the line crosses the y axis and therefore has no bearing on the gradient.

Step 3: Put the differentiated parts back together to give the differentiated equation

dy/dx=15x2-4x+7

MT
Answered by Matthew T. Maths tutor

13072 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A particle of mass 0.25 kg is moving with velocity (3i + 7j) m s–1, when it receives the impulse (5i – 3j) N s. Find the speed of the particle immediately after the impulse.


Prove that 2 cot (2x) + tan(x) == cot (x)


evaluate the integral of lnx


Derive from the standard quadratic equation, the form of the quadratic solution


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning