Find dy/dx for y=5x^3-2x^2+7x-15

Step 1: To differentiate an equation there is a simple rule to follow. For y=axn dy/dx=anxn-1. so for an example y=x3, dy/dx=3x2. Therefore we just apply this rule into our equation.

Step 2: Break the equation down and do each factor of x seperately so 5x3 differentiates into 15x2, -2x2 differentiates to -4x, 7x differentiates to 7 and the 15 disappears from the end. This happens as the 15 just tells us where the line crosses the y axis and therefore has no bearing on the gradient.

Step 3: Put the differentiated parts back together to give the differentiated equation

dy/dx=15x2-4x+7

MT

Related Maths A Level answers

All answers ▸

If f(x)=(4x^2)-(8x)+3, find the gradient of y=f(x) at the point (0.5,0)


How do I integrate x/(x^2 + 3) ?


Find the gradient of a curve whose parametric equations are x=t^2/2+1 and y=t/4-1 when t=2


Find the derivative with respect to x and the x-coordinate of the stationary point of: y=(4x^2+1)^5