Find dy/dx for y=5x^3-2x^2+7x-15

Step 1: To differentiate an equation there is a simple rule to follow. For y=axn dy/dx=anxn-1. so for an example y=x3, dy/dx=3x2. Therefore we just apply this rule into our equation.

Step 2: Break the equation down and do each factor of x seperately so 5x3 differentiates into 15x2, -2x2 differentiates to -4x, 7x differentiates to 7 and the 15 disappears from the end. This happens as the 15 just tells us where the line crosses the y axis and therefore has no bearing on the gradient.

Step 3: Put the differentiated parts back together to give the differentiated equation

dy/dx=15x2-4x+7

MT

Related Maths A Level answers

All answers ▸

Demonstrate that (2^n)-1 is not a perfect square for any n>2, n ∈ N.


Express cos(2x) in terms of acos^2(x) + b


It is given f(x)=(19x-2)/((5-x)(1+6x)) can be expressed A/(5-x)+B/(1+6x) where A and B are integers. i) Find A and B ii) Show the integral of this from 0 to 4 = Kln5


A circle with centre C(2, 3) passes through the point A(-4,-5). (a) Find the equation of the circle in the form (x-a)^2 + (y-b)^2=k