Two particles A and B of mass 2kg and 3kg respectively are moving head on. A is moving at 5m/s and B is moving at 4m/s. After the collision, A rebounds at 4m/s. What is the speed of B and what direction is it moving in?

Using conservation of momentum, m1u1 + m2u2 = m1v1 + m2v2, set m1 = 2kg, m2 = 3kg, u1 = 5m/s, u2 = -4m/s and v1 = -4m/s. Substitute these into the equation to get 25 + 3(-4) = 2*(-4) + 3*v2 10 - 12 = -8 +3v2 6 = 3v2 v2 = 2m/s and is moving in the positive direction, away from A.

AS
Answered by Amber S. Maths tutor

4729 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The height (h) of water flowing out of a tank decreases at a rate proportional to the square root of the height of water still in the tank. If h=9 at t=0 and h=4 at t=5, what is the water’s height at t=15? What is the physical interpretation of this?


Express cos(2x) in terms of acos^2(x) + b


Solve the equation: 2x+3y=8 & 3x-y=23


Find the equation of the tangent to the curve y^3 - 4x^2 - 3xy + 25 = 0 at the point (2,-3).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences