Solve the simultaneous equation 2x-4y=8 and 3x+3y=-15

Set 2x-4y=8 as equation 1, and 3x+3y=-15 as equation 2. Multiply equation 1 by 3 and equation 2 by 4 so they look like 6x-12y=24 and 12x+12y=-60. Now add the two equations and you get 18x=-36 or x=-2. Substitute this back into equation 2 and you get -6+3y=-15. Add 6 to both sides and you get 3y=-9 or y=-3.

DL
Answered by Daniel L. Maths tutor

4037 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve: 3^(x^2-5x+2)=9^(x+1)


2x + y = 1, x^2 + y^2 = 1


A is the point (2,-5), B is the point (-1,4). (a) What is the gradient of the line passing through points A and B? (b) Does the point (-100,301) lie on the line passing through points A and B?


Integrate (x+2)^2 dx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning