How do you approach a simultaneous equations problem?

There should be at least as many simultaneous equations as there are unknown variables - or else you cannot get a numerical answer! Start by trying to eliminate one of the variables. You can multiply the equation by an integer to eliminate variables but remember to multiply both sides! Then subsitiute the value you have found back into one of the original equations. This will give you your answer.

Example:

4x+2y+z=11    (1)

3x+2y+2z=13     (2)

x+y+z=6    (3)

First, do (2)-(1), giving -x+z=2, and hence z=x+2

Then subsitute this into (3). This gives x+y+x+2=6, 2x+y=4 (4). If you double (4), you get 4x+2y=8 (5). Then do (1)-(5) to get z=3. We know z=x+2, so x=1. If we substitute both of these into (3), we find y=2. Thus this set of equations is solved.

AH
Answered by Annie H. Maths tutor

3301 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If I put £500 in the bank with an annual interest rate of 3% how much money will I have earned in 2 years?


Solve the simultaneous equations: 2x + 3y = 5 and 3x + 4y = 12


Factorising and Expanding brackets


Solve "x^2 - 12x - 45 = 0" by completing the square


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning