Solve algebraically: 6a + b = 16 ..... 5a - 2b = 19

first equation: 6a + b = 16     second equation: 5a - 2b = 19    from 2 times first equation + second equation 17a = 51 meaning a = 3

.... from the first equation 6(3) + b = 16 therefore b = - 2

Answered by Benjamin C. Maths tutor

2192 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the inverse of the following function: g(x) = 4/(3-x)


(3 + root(a))(4 + root(a)) = 17 + k(root(a)) where a and k are positive integers. Find the value of a and the value of k.


A linear sequence starts a + 2b, a + 6b, a + 10b … The 2nd term has value 8 The 5th term has value 44 Work out the values of a and b.


Consider an isosceles triangle ABC, where AB=AC=1, M is the midpoint of BC, and <BAM=<CAM=x. Use trigonometry to find an expression for BM and by finding BC^2, show that cos2x = 1 - 2(sinx)^2.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy